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<blockquote data-quote="a33" data-source="post: 1034216" data-attributes="member: 332642">I guess what you might be meaning here is that with a motor axis parallel to the earth's polar axis, but not at the poles themselves, there is a mismatch of the 'aiming circle' of the motor with the clarke belt circle.This, however, has NOTHING to do with a non-spherical earth.And this problem is in fact, as can be read throughout this topic and also in my post, 'solved' by using MODIFIED motor elevation and modified declination angle.I read this topic again carefully: <a href="https://www.satelliteguys.us/xen/threads/usals-notebook.166471/" target="_blank">USALS Notebook</a>&nbsp; , and in the posts of [USER=259750]@pendragon[/USER] it also sais that it never is fully perfect, and it might still leave errors of some hundredth of degrees.However I find the [USER=301161]@Huevos[/USER] method easy to calculate in a spreadsheet calculator, and accept that that also is not without a little tracking error.Thanks for responding!Greetz,A33</blockquote>

[QUOTE="a33, post: 1034216, member: 332642"] I guess what you might be meaning here is that with a motor axis parallel to the earth's polar axis, but not at the poles themselves, there is a mismatch of the 'aiming circle' of the motor with the clarke belt circle. This, however, has NOTHING to do with a non-spherical earth. And this problem is in fact, as can be read throughout this topic and also in my post, 'solved' by using MODIFIED motor elevation and modified declination angle. I read this topic again carefully: [URL="https://www.satelliteguys.us/xen/threads/usals-notebook.166471/"]USALS Notebook[/URL] , and in the posts of [USER=259750]@pendragon[/USER] it also sais that it never is fully perfect, and it might still leave errors of some hundredth of degrees. However I find the [USER=301161]@Huevos[/USER] method easy to calculate in a spreadsheet calculator, and accept that that also is not without a little tracking error. Thanks for responding! Greetz, A33 [/QUOTE]

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